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0=-16t^2+115t+3
We move all terms to the left:
0-(-16t^2+115t+3)=0
We add all the numbers together, and all the variables
-(-16t^2+115t+3)=0
We get rid of parentheses
16t^2-115t-3=0
a = 16; b = -115; c = -3;
Δ = b2-4ac
Δ = -1152-4·16·(-3)
Δ = 13417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-\sqrt{13417}}{2*16}=\frac{115-\sqrt{13417}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+\sqrt{13417}}{2*16}=\frac{115+\sqrt{13417}}{32} $
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